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Question

In the figure given below, P=RTS.
Prove that RPQsinRTS.
1008692_5d1b4d16cbf74622a95106f5fde6ffb3.jpg

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Solution

In triangles RPQ and RTS, we have

RPQ=RTS [Given]

PRQ=TRS [Each equal to R]

Therefore, by AA-criterion of similarity, we have

RPQRTS. [Hence proved]


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