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Triangles

In the figure...

Question

In the figure given below BC is parallel to DE and AD = 7, DB = 1, AE = 14. Find EC.

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Solution

The correct option is C
2

$Δ$ ADE $\sim Δ$ ABC $\Rightarrow \frac{A D}{A B}$ = $\frac{A E}{A C}$ Solving we get EC = 2.

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D E

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