Question

In the figure, given below, CD is parallel to AB. Calculate $\angle$y

• A. ${60}^{\circ }$
• B. ${62}^{\circ }$
• C. ${69}^{\circ }$
• D. ${68}^{\circ }$

Answer 1

The correct option is A ${60}^{\circ }$

Sum of angles of triangle $ABC={180}^o$
$4x+2x+3x={180}^o$
$9x={180}^o$
$x={20}^o$
thus, $\angle ABC=3x={60}^{\circ }$
$y=\angle ABC$ (Corresponding angles of parallel lines AB and CD)
$y={60}^{\circ }$