Question

In the figure given below, E is the mid-point of AB and F is the midpoint of AD. If the area of FAEC is 13, what is the area of ABCD?

• A. 19.5
• B. 26
• C. 39
• D. None of these

Answer 1

The correct option is B

26

As F is the mid-point of AD, CF is the median of the triangle ACD to the side AD.
Hence, area of the triangle FCD = area of the triangle ACF.
Similarly area of triangle BCE = area of triangle ACE.
$\therefore$ Area of ABCD = Area of (CDF + CFA + ACE + BCE)
= 2 Area (CFA + ACE) = 2 $\times$ 13 = 26 sq. units.