In the figure given below, find the value of y.

100^{\circ}

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40^{\circ}

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80^{\circ}

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60^{\circ}

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Solution

The correct option is A $100^{\circ}$
$30^{\circ} + 15^{\circ} + 35^{\circ} + y = 180^{\circ}$
$30^{\circ} + 50^{\circ} + y = 180^{\circ}$
$y = 180^{\circ} - 80^{\circ}$
$y = 100^{\circ}$

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Similar questions

In the below figure find the value of $∠ Q O R$ . Given that $∠ Q S R = 40^{\circ}$ and O is the centre of the circle.

∠ A C D = 120^{\circ}

∠ B C D

$In the given figure, O is the centre of a circle. If ∠ A O B = 40^{\circ} a n d ∠ B D C = 100^{\circ} t h e n f i n d ∠ O B C .$

y

x = 60 °

x

y = 40 °

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