In the figure given below, if ∠AOP=75∘ and ∠AOB=120∘, the what is ∠AQP?
A
45∘
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B
37.5∘
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C
30∘
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D
22.5∘
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Solution
The correct option is B37.5∘ Here, ∠AOP is subtended by the arc AP at the centre of the circle. And, ∠AQP is subtended by the arc AP at the point Q on the circle. We know that the angle subtended by an arc of a circle at the centre of the circle is double the angle subtended by it at any point on the circle. So, ∠AOP=2∠AQP ⇒∠AQP=12∠AOP=12×75∘=37.5∘