In the figure given below- if BC EF and FG CD - AE - ABA- AG - GDB- GD-AGC- AG-ADD- CF-AF

The correct option is C AG/AD In the Δ ABC, EF ∥ BC ∴ AE/AB = AF/AC ......(1) [By BPT] In Δ ACD, FG ∥ CD ∴ AF/AC = AG/AD .......(2) [By BPT] From (1) an ...

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Byju's Answer

Standard X

Mathematics

Basic Proportionality Theorem

In the figure...

Question

In the figure given below, if BC $∥$ EF and FG $∥$ CD. $\frac{A E}{A B}$ =

AG/GD

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GD/AG

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AG/AD

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CF/AF

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Solution

The correct option is C
AG/AD

In the $Δ$ ABC,
EF $∥$ BC
$∴$ $\frac{A E}{A B}$ = $\frac{A F}{A C}$ ......(1) [By BPT]

In $Δ$ ACD,
FG $∥$ CD
$∴$ $\frac{A F}{A C}$ = $\frac{A G}{A D}$ .......(2) [By BPT]

From (1) and (2), we get
$\frac{A E}{A B}$ = $\frac{A F}{A C}$ = $\frac{A G}{A D}$
$\Rightarrow \frac{A E}{A B}$ = $\frac{A G}{A D}$

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In the figure given below, if BC ∥ EF and FG ∥ CD. AEAB =

The correct option is C AG/AD In the Δ ABC, EF ∥ BC ∴ AEAB = AFAC ......(1) [By BPT] In Δ ACD, FG ∥ CD ∴ AFAC = AGAD .......(2) [By BPT] From (1) and (2), we get AEAB = AFAC = AGAD ⇒AEAB = AGAD

In the figure given below, if BC $∥$ EF and FG $∥$ CD. $\frac{A E}{A B}$ =