Question

In the figure given below in $\Delta PQR$, seg $RS$ is the angle bisector of $\angle PRQ$. If $PS=4,SQ=6,PR=10$, find $QR$.

Answer 1

Seg RS bisects $\angle PRQ$ (Given)
$\therefore \frac{PR}{QR}=\frac{PS}{SQ}$ (Angle bisector property)
$\therefore \frac{10}{QR}=\frac{4}{6}$ (Substituting the given values)
$\therefore 10\times 6=4\times QR$
$\therefore \frac{10\times 6}{4}=QR$
$\therefore QR=15$