Question

In the figure given below, $LM=LN$; angle $PLN={110}^o$.
Calculate:
$\angle MLN$

Answer 1

In $\Delta LMN$,
$\angle LMN+\angle LNM+\angle MLN={180}^o$
But, $\angle LNM=\angle LMN={70}^o$ [from(i) and (ii)]
$\therefore {70}^o+{70}^o+\angle MLN={180}^o$
$\Rightarrow \angle MLN={180}^o-{140}^o$
$\Rightarrow \angle MLN={40}^o$