Question

In the figure given below, LOM is a straight line. What is the value of x?

Answer 1

From the given figure,
$\angle LOM+\angle QOP+\angle POM={180}^o$ [Sum of angles formed on a straight line]$\left[1mark\right]$
⇒ $(x+{20}^o)+{50}^o+(x-{10}^o)={180}^o$
⇒ $2x+{60}^o={180}^o$
⇒ $2x={120}^o$
⇒ $x={60}^o$$\left[1mark\right]$