Question

In the figure given below, normally in two jumps frog covers the distance of 9m. One day on seeing the snake frog jumped $\frac{1}{5}$ times more than his normal jump and again he jumped with full strength and covered $\frac{1}{2}$ times more distance than he normally covers in the end of second jump. Find the distance covered by frog in second jump and in total. [4 MARKS]

Answer 1

Calculation : 2 Marks
Result : 2 Mark

In normal jump frog covers 5m in first jump but this time his jump covered = 5 + (5 $\times$ $\frac{1}{5}$) = 6m

In the second jump it covered = 4m + (4 $\times$ $\frac{1}{2}$) = 6m.

So, distance covered in second jump = 6m.
Total distance covered by frog = 6m + 6m = 12m