Question

In the figure given below, point D divides AB in the ratio 3 : 5 and DE is parallel to BC. If AE = 4.8 cm, then find the length of AC.

Answer 1

Given that,
Point D divides AB in the ratio 3:5.

So,
$\frac{AD}{DB}=\frac{3}{5}$

Since DE || BC,
$\frac{AE}{EC}=\frac{AD}{DB}$
$\frac{AE}{EC}=\frac{3}{5}$

Given:
AE = 4.8 cm
$\frac{4.8}{EC}=\frac{3}{5}$

Now,
EC = 8 cm
AC = AE + EC = 4.8 + 8 = 12.8 cm