In the figure given below PT is a tangent to the circle- The ratio PA - PB - CD - BD -A- PT - TDB- PT - TD 2C- PT - PD 2D- PD-PT

The correct option is B ( PT / TD )2 PA.PB=PT^2 – (i) ⇒ DC.DB= DT^2 – (ii) ∴(i) (ii) → ⇒ PA.PB/DC.DB=(PT/DT)^2 ...

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In the figure...

Question

In the figure given below PT is a tangent to the circle. The ratio

$\frac{P A \times P B}{C D \times B D}$ =?

PT / TD

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( PT / TD )²

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( PT / PD )²

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PD/PT

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Solution

The correct option is B
( PT / TD )²

PA.PB=PT $^{2}$ -- (i)

$\Rightarrow$ DC.DB= DT $^{2}$ -- (ii)

$∴$ (i) (ii) →

$\Rightarrow \frac{P A . P B}{D C . D B} = {(\frac{P T}{D T})}^{2}$

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In the figure given below PT is a tangent to the circle. The ratio PA×PBCD×BD=?

The correct option is B ( PT / TD )2 PA.PB=PT2 -- (i) ⇒ DC.DB= DT2 -- (ii) ∴(i) (ii) → ⇒ PA.PBDC.DB=(PTDT)2

In the figure given below PT is a tangent to the circle. The ratio

$\frac{P A \times P B}{C D \times B D}$ =?

The correct option is B
( PT / TD )²

PA.PB=PT $^{2}$ -- (i)

$\Rightarrow$ DC.DB= DT $^{2}$ -- (ii)

$∴$ (i) (ii) →

$\Rightarrow \frac{P A . P B}{D C . D B} = {(\frac{P T}{D T})}^{2}$