In the figure given below- the lengths PQ WCB-30- and QR WCB-45- respectively up to three places of decimal are

Length of PQ=l_1 Length of QR =l_2 l_1cos 30+l_2 cos 45 =(1000 100) l_1cos 30+l_2 cos 45 =900 nbsp; ...(1) and nbsp;l_1sin 30+l_2 sin 45 ...

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Standard XII

Mathematics

Pedal Triangle

In the figure...

Question

In the figure given below, the lengths $P Q (W C B : 30^{\circ}) a n d Q R (W C B : 45^{\circ})$ respectively up to three places of decimal are

551.815, 551.815

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273.205, 551.815

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551.815, 938.186

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273.205, 938.186

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Solution

The correct option is D 273.205, 938.186
$L e n g t h o f P Q = l_{1}$

$L e n g t h o f Q R = l_{2}$

$l_{1} cos 30 + l_{2} cos 45 = (1000 - 100)$

$l_{1} cos 30 + l_{2} cos 45 = 900 . . . (1)$

and $l_{1} sin 30 + l_{2} sin 45 = (1000 - 200)$

$l_{1} sin 30 + l_{2} sin 45 = 800 . . . (2)$

Solving equation (1) and (2),

$l_{1} = 273.205$

$l_{2} = 938.186$

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In the figure given below, the lengths PQ(WCB:30∘) and QR(WCB:45∘) respectively up to three places of decimal are

The correct option is D 273.205, 938.186Length of PQ=l1 Length of QR=l2 l1cos30+l2cos45=(1000−100) l1cos30+l2cos45=900 ...(1) and l1sin30+l2sin45=(1000−200) l1sin30+l2sin45=800 ...(2) Solving equation (1) and (2), l1=273.205 l2=938.186

In the figure given below, the lengths $P Q (W C B : 30^{\circ}) a n d Q R (W C B : 45^{\circ})$ respectively up to three places of decimal are