In the figure given below, the magnitude of normal reaction exerted by the floor on the 50 kg block is [The string and pulley are massless and all the surfaces are smooth] [Take g=10m/s2]
A
300 N
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B
500 N
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C
200 N
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D
700 N
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Solution
The correct option is A 300 N Let T be the tension in the string and R be the normal reaction force on the block of mass 50 kg applied by the floor. m1=50kg m2=20kg
For the block of mass m2 (20 kg):
At equilibrium, T=m2g=20g
For the block of mass m1 (50 kg): T+R=m1g ⇒R=m1g–T ⇒R=50g–20g=30g ⇒R=300N(∵g=10m/s2)
Hence, the correct answer is option (1).