In the figure, given below, triangle ABC is right-angled at B: ABPQ and ACRS are squares.Prove that :
(i) Δ ACQ and Δ ASB are congruent.
(ii) CQ =BS.
∠QAC = ∠QAB+∠BAC=900+x
In △QAC and △ BAS
QA = AB (sides of same square)
AS = AC (sides of same square)
Thus, Δ ACQ is congruent to Δ ASB (SAS)