In the figure given $P M = 10 c m, M N = 15$ cm and $P N = 17$ cm Also $Q M = Q X = R N$ . Perimeter of the $Δ P Q R$ is

32

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27

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25

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21

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Solution

The correct option is A $27$
Since triangles QMX and RNX are both isosceles, we have $Q X = Q M$ and $X R = R N$ . So the perimeter $= P Q + Q X + X R + R P$
$= (P Q + Q M) + (P R + R N)$
$= P M + P N = 10 + 17 = 27$

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Similar questions

Q. In the given figure, a circle inscribed in

Δ P Q R

with PQ = 10 cm, QR = 8 cm. PR= 12 cm, find the length QM, RN and PL.

Q. In

Δ P Q R, M N | | Q R

and given that PM = 3 cm MQ = 8cm, QR = 32 then MN is (image)

Q. PM =4 cm; QM =4.5 cm;
PN = 4 cm; NR = 4.5 cm

M and N are points on the sides PQ and PR respectively of a $Δ P Q R$ . For each of the following cases, whether MN || QR:
(i) PM = 4 cm, QM = 4.5 cm, PN = 4 cm, NR = 4.5 cm
(ii) PQ =1.28 cm, PR = 2.56 cm, PM = 0.16 cm, PN = 0.32 cm

Q. M and N are points on the sides PQ and PR respectively of a

△

PQR. For each of the following cases, state whether MN

∥

QR :

(i) PM = 4 cm,QM = 4.5 cm, PN = 4 cm, NR = 4.5 cm

(ii) PQ = 1.28 cm, PR = 2.56 cm, PM = 0.16 cm, PN = 0.32 cm

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In the figure given PM=10cm,MN=15 cm and PN=17 cm Also QM=QX=RN. Perimeter of the ΔPQR is

The correct option is A 27Since triangles QMX and RNX are both isosceles, we have QX=QM and XR=RN. So the perimeter=PQ+QX+XR+RP=(PQ+QM)+(PR+RN)=PM+PN=10+17=27

In the figure given $P M = 10 c m, M N = 15$ cm and $P N = 17$ cm Also $Q M = Q X = R N$ . Perimeter of the $Δ P Q R$ is

The correct option is A $27$
Since triangles QMX and RNX are both isosceles, we have $Q X = Q M$ and $X R = R N$ . So the perimeter $= P Q + Q X + X R + R P$
$= (P Q + Q M) + (P R + R N)$
$= P M + P N = 10 + 17 = 27$