In the figure given, PR = 22 cm, SN = MQ = 3 cm. What is the area of PQRS?
A
66 cm2
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B
63 cm2
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C
34 cm2
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D
198 cm2
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Solution
The correct option is A 66 cm2 In the given figure, PR = 22 cm and SN = MQ = 3 cm. The given rectangle can be considered as the combination of two triangles i.e. △PSR and △PQR. Now , area of rectangle PQRS = Area of △PSR + Area of △PQR Area of △PSR = 12×SN×PR = 12×3×22 = 3 × 11 = 33 cm2
Area of △PQR = 12×QM×PR = 12×3×22 = 3 × 11 = 33 cm2 ⇒ Area of the rectangle = 33 cm2 + 33 cm2 = 66 cm2 Therefore, area of the given figure is 66 cm2.