In the figure, given that VBB supply can vary from 0 to5.0V,VCC=5V,βdc=200,RB=100kΩ,RC=1kΩ and VBE=1.0V. The minimum base current and the input voltage at which the transistor will go to saturation, will be respectively:
A
20μA and 3.5V
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B
25μA and 3.5V
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C
25μA and 2.5V
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D
20μA and 2.8V
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Solution
The correct option is B25μA and 3.5V At saturation, VCE=0 VCE=VCC−ICRC IC=VCCRC=5×10−3A Given βdc=ICIB IB=5×10−3200 IB=25muA At input side VBB=IBRB+VBE =(25mA)(100kΩ)+1V VBB=3.5V