In the figure, if $A B = A C a n d ∠ B = ∠ C .$

Prove that BQ = CP.

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Solution

Given : In the figure, $A B = A C, ∠ B = ∠ C$

To prove : $B Q = C P$

Proof : In $Δ A B Q a n d Δ A C P$

AB = AC (Given)

$∠ A = ∠ A (C o m m o n)$

$∠ B = ∠ C (G i v e n)$

$∴ Δ A B Q ≅ Δ A C P (ASA axiom)$

$∴ B Q = C P (c . p . c . t .)$

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Similar questions

A B = A C

A P = A Q

C P = B Q

△ A B C, A B = A C, a n d C P a n d B Q

C P = B Q

Δ

∠

⊥

⊥

B C^{2} = (A C \times C P + A B \times B Q)

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