Question

In the figure, if AB = CD and $\angle ABO={35}^{\circ }$.
Then, the value of $\angle DCO={35}^{\circ }$
'O' is the centre of the circle

• A. 35
• B. False

Answer 1

The correct option is A

35

OB = OC (Radii of the same circle)

OA = OD (Radii of the same circle)

AB = CD (Given)

$△AOB\cong △DOC$
(By SSS congruence condition)

So, $\angle ABO=\angle DCO={35}^{\circ }$
(Corresponding parts of congruent triangles)