In the figure if AD = BC and $A D ∥ B C$ then

AB = DC

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AB = AD

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BC = CD

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DC = AC

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Solution

The correct option is C AB = DC
In the given figure
AD = BC, AC = AC
$∠ A D C = ∠ A B C$ ( $∵ A D ∥ B C$ )
By SAS theorem $△ A B C \equiv△ C D A$
so AB = DC

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Similar questions

In the given figure, if AD = BC and AD || BC, then

Factorize $(a^{2} - b^{2}) (c^{2} - d^{2}) - 4 a b c d$

A C + B D = A D + B C

A B + C D = A D - B C

A D

=

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A D

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B C

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