Then - AOC is equal toA 20-B 40-C 60-D 10-

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Standard X

Mathematics

Recall Arc, Central Angle and Measure of an Arc

then ∠ AOC is...

Question

Question 4
In the figure, if $∠ A B C = 20^{\circ}$ , then $∠ A O C$ is equal to

(A) $20^{\circ}$
(B) $40^{\circ}$
(C) $60^{\circ}$
(D) $10^{\circ}$

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Solution

The answer is B.
Given, $∠ A B C = 20^{\circ}$
We know that, angle subtended at the centre by an arc is twice the angle subtended by it at the remaining part of the circle.
$∠ A O C = 2 ∠ A B C = 2 \times 20^{\circ} = 40^{\circ}$

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Similar questions

Q. Question 4
In the figure, if

∠ A B C = 20^{\circ}

, then

∠ A O C

is equal to

(A) 20º
(B) 40º
(C) 60º
(D) 10º

Q. Question 4
In the figure, if

∠ A B C = 20^{\circ}

, then

∠ A O C

is equal to

(A)

20^{\circ}

(B)

40^{\circ}

(C)

60^{\circ}

(D)

10^{\circ}

In the given figure, AB || CD.If $∠ B A O = 60^{\circ}$ and $∠ O C D = 110^{\circ}$ then $∠ A O C = ?$

$(a) 70^{\circ}$

$(b) 60^{\circ}$

$(c) 50^{\circ}$

$(d) 40^{\circ}$

Q. In the given figure, AOB is a straight line. If ∠AOC = (3x − 10)°, ∠COD = 50° and ∠BOD = (x + 20)°, then ∠AOC = ?
(a) 40°
(b) 60°
(c) 80°
(d) 50°

In the given figure, AOB is a straight line. If $∠ A O C = (3 x - 10)^{\circ}$ , \angle COD = 50^{\circ}\) and $∠ B O D = (x + 20)^{\circ}$ then $∠ A O C = ?$

(a) $40^{\circ}$

(b) $60^{\circ}$

(d) $50^{\circ}$

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Question 4 In the figure, if ∠ABC=20∘, then ∠AOC is equal to (A) 20∘ (B) 40∘ (C) 60∘ (D) 10∘

The answer is B. Given, ∠ABC=20∘ We know that, angle subtended at the centre by an arc is twice the angle subtended by it at the remaining part of the circle. ∠AOC=2∠ABC=2×20∘=40∘

Question 4
In the figure, if $∠ A B C = 20^{\circ}$ , then $∠ A O C$ is equal to

(A) $20^{\circ}$
(B) $40^{\circ}$
(C) $60^{\circ}$
(D) $10^{\circ}$

The answer is B.
Given, $∠ A B C = 20^{\circ}$
We know that, angle subtended at the centre by an arc is twice the angle subtended by it at the remaining part of the circle.
$∠ A O C = 2 ∠ A B C = 2 \times 20^{\circ} = 40^{\circ}$