Question

In the figure if $\angle AOC=\angle BOD,\angle AOB={45}^{\circ }\angle BOD={60}^{\circ }$ then find $\angle BOC$.

Answer 1

$Given\angle AOC=\angle BOD$

$\Rightarrow \angle AOB+\angle BOC=\angle BOD$ $[\because \angle AOC=\angle AOB+\angle BOC]$

$\Rightarrow \angle BOC=\angle BOD-\angle AOB$

$Given\angle BOD={60}^o\&\angle AOB={45}^o$

$So\angle BOC=60-45$

$\Rightarrow \angle BOC={15}^o$