In the figure if DE = BF = 7 cm and AC = 9 cm. Find the area of the parallelogram.

$63 c m^{2}$

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$126 c m^{2}$

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$31.5 c m^{2}$

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$70 c m^{2}$

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Solution

The correct option is A
$63 c m^{2}$

Area of ABCD = area of $Δ A B C$ + area of $Δ A C D$
$= \frac{1}{2} \times 9 \times 7 + \frac{1}{2} \times 9 \times 7$
$= \frac{63}{2} + \frac{63}{2}$
$= 63 c m^{2}$

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In the figure if DE = BF = 7 cm and AC = 9 cm. Find the area of the parallelogram.

The correct option is A 63 cm2 Area of ABCD = area of ΔABC + area of ΔACD =12×9×7+12×9×7 =632+632 =63 cm2

The correct option is A
$63 c m^{2}$

Area of ABCD = area of $Δ A B C$ + area of $Δ A C D$
$= \frac{1}{2} \times 9 \times 7 + \frac{1}{2} \times 9 \times 7$
$= \frac{63}{2} + \frac{63}{2}$
$= 63 c m^{2}$