In the figure if DE = BF = 7 cm and AC = 9 cm. Find the area of the parallelogram.

$63 c m^{2}$

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$31.5 c m^{2}$

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$126 c m^{2}$

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$70 c m^{2}$

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Solution

The correct option is A
$63 c m^{2}$

Area of ABCD = area of $Δ A B C$ + area of $Δ A C D$
$= \frac{1}{2} \times 9 \times 7 + \frac{1}{2} \times 9 \times 7$
$= \frac{63}{2} + \frac{63}{2}$
$= 63 c m^{2}$

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Question 102

ABCD is a parallelogram in which AE is perpendicular to CD is shown in the given figure. Also, AC = 5 cm, DE = 4 cm and area of $Δ A E D = 6 c m^{2}$ .
Find the perimeter and area of parallelogram ABCD.

In the figure if DE = BF = 7 cm and AC = 9 cm. Find the area of the parallelogram.

Q. Triangles ABC and DEF are similar.

(i) If area (∆ABC) = 16 cm², area (∆DEF) = 25 cm² and BC = 2.3 cm, find EF.
(ii) If area (∆ABC) = 9 cm², area (∆DEF) = 64 cm² and DE = 5.1 cm , find AB.
(iii) If AC = 19 cm and DF = 8 cm, find the ratio of the area of two triangles.
(iv) If area (∆ABC) = 36 cm², area (∆DEF) = 64 cm² and DE = 6.2 cm, find AB.
(v) If AB = 1.2 cm and DE = 1.4 cm, find the ratio of the areas of ∆ABC and ∆DEF.

Q. In the figure, ABCD is a parallelogram. If DE

=

4 cm, then BF equals :

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Standard VII Mathematics

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In the figure if DE = BF = 7 cm and AC = 9 cm. Find the area of the parallelogram.

The correct option is A 63 cm2 Area of ABCD = area of ΔABC + area of ΔACD =12×9×7+12×9×7 =632+632 =63 cm2

The correct option is A
$63 c m^{2}$

Area of ABCD = area of $Δ A B C$ + area of $Δ A C D$
$= \frac{1}{2} \times 9 \times 7 + \frac{1}{2} \times 9 \times 7$
$= \frac{63}{2} + \frac{63}{2}$
$= 63 c m^{2}$