In the figure, if line segment AB is parallel to the line segment CD, what is the value of y?

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Solution

The correct option is D
20

In the figure, AB || CD BD is transversal
$∴ ∠ A B D + ∠ B D C = 180^{0}$
(Co-interior angles)
$\Rightarrow y + 2 y + y + 5 y = 180^{0}$
$\Rightarrow 9 y = 180^{0} \Rightarrow y = \frac{180^{0}}{9} = 20^{0}$

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In the figure, if line segment AB is parallel to the line segment CD, what is the value of y?

The correct option is D 20 In the figure, AB || CD BD is transversal ∴∠ABD+∠BDC=1800 (Co-interior angles) ⇒y+2y+y+5y=1800 ⇒9y=1800⇒y=18009=200

The correct option is D
20

In the figure, AB || CD BD is transversal
$∴ ∠ A B D + ∠ B D C = 180^{0}$
(Co-interior angles)
$\Rightarrow y + 2 y + y + 5 y = 180^{0}$
$\Rightarrow 9 y = 180^{0} \Rightarrow y = \frac{180^{0}}{9} = 20^{0}$