Question

In the figure if $PQ\parallel ST,\angle PQR={110}^o$ and $\angle RST={130}^o$, find $\angle QRS$

Answer 1

ref image

$\angle A=\angle RST={130}^o$

$\angle B+{110}^o={180}^o\Rightarrow \angle B={70}^o$

$\angle A=\angle B+\angle C$

$\angle C=\angle A-\angle B$

$\angle C={130}^o-{70}^o$

$\angle QRS={60}^o$