Question

In the figure, it is given that AB = AC and point D bisects the side BC.
$\text{Enter the value of}\angle ADC\text{in degrees}$.

• A. 90

Answer 1

The correct option is A 90
Given, AB = AC.
Also it is given that D bisects side BC.
So, BD = DC.
And, AD = AD (common side)
$\therefore △$ADB $\cong$ $△$ADC [S.S.S congruency]
Thus, $\angle$ADB = $\angle$ADC (CPCT) $\cdots \left(1\right)$
But, $\angle$ADB + $\angle$ADC = ${180}^{\circ }$ [linear pair of angles]
i.e., $2\angle ADC={180}^{\circ }$ (from (1))
$⟹\angle ADC={90}^{\circ }$