Question

In the figure, it is given that AB = CD and AD = BC. Prove that $\Delta ADC\cong \Delta CBA.$

Answer 1

Given : In the figure AB = CD, AD = BC

To prove : $\Delta ADC\cong \Delta CBA$

Proof : In $\Delta ADCand\Delta CBA$

CD = AB (Given)

AD = BC (Given)

CA = CA (Common)

$\therefore \Delta ADC\cong \Delta CBA$ (SSS axiom)