In the figure, $L, M a n d N$ are respectively the mid-points of sides $A B, B C a n d C A$ of $△ A B C$
$C P$ is $_____$ corresponding to the side $A B$

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Solution

In the figure,
$C P$ is perpendicular drawn from the vertex $C$ of the triangle to the opposite side $A B$
and we know that,
An altitude of a triangle is the perpendicular drawn from any vertex of the triangle to the opposite side.
Hence, $C P$ is an altitude corresponding to the side $A B$

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In ΔABC, we have AB : BC = 2 : 3 and BC : CA = 4 : 5. What is AB : BC : CA?

Q. In Figure, which of the following is not true?

(a)

\vec{A B} + \vec{B C} + \vec{C A} = \vec{0}

(b)

\vec{A B} + \vec{B C} - \vec{A C} = \vec{0}

(c)

\vec{A B} + \vec{B C} - \vec{C A} = \vec{0}

(d)

\vec{A B} - \vec{C B} + \vec{C A} = \vec{0}

Figure

In the figure, $L, M a n d N$ are respectively the mid-points of sides $A B, B C a n d A C$ of $△ A B C .$
$C L$ is $______$ corresponding to the side $A B .$

In the figure, $L, M a n d N$ are respectively the mid-points of the sides $A B, B C a n d A C$ of $△ A B C$

$A Q$ is $____$ corresponding to the side $B C$ .

Q. In the figure sides

A B, B C, C A

△ A B C

are produced upto points

R, F, P

respectively such that

A B = B R, B C = C P, C A = A F

Prove that :

A (△ P E R) = 7 A (△ A B C)

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In the figure, L,MandN are respectively the mid-points of sidesAB,BCandCAof △ABCCP is_____ corresponding to the sideAB

In the figure,CP is perpendicular drawn from the vertexC of the triangle to the opposite side ABand we know that,An altitude of a triangle is the perpendicular drawn from any vertex of the triangle to the opposite side.Hence, CP is an altitude corresponding to the side AB

In the figure, $L, M a n d N$ are respectively the mid-points of sides $A B, B C a n d C A$ of $△ A B C$
$C P$ is $_____$ corresponding to the side $A B$

In the figure,
$C P$ is perpendicular drawn from the vertex $C$ of the triangle to the opposite side $A B$
and we know that,
An altitude of a triangle is the perpendicular drawn from any vertex of the triangle to the opposite side.
Hence, $C P$ is an altitude corresponding to the side $A B$