Question

In the figure (not drawn to scale), $ABC$ and $DEF$ are two triangles, $CA$ is parallel to $FD$ and $CFBE$ is a straight line. Find the value of $x+y$

• A. ${185}^o$
• B. ${134}^o$
• C. ${158}^o$
• D. ${176}^o$

Answer 1

The correct option is A ${185}^o$

$\angle FCA=\angle BFD$

$\Rightarrow x={51}^o$ .....(Crresponding angles)
Now in $△ABC$ , we have

$y={51}^o+{83}^o$ .....By using exterior angle property

$\Rightarrow y={134}^o$
So, $x+y={51}^o+{134}^o={185}^o$