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Question

In the figure(not drawn to scale), ABC and DEF are two triangles, CA is parallel to FD and CFBE is a straight line. Find the value of x+y.
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A
185o
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B
134o
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C
148o
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D
176o
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Solution

The correct option is A 185o
Given that CA is parallel to FD and CFBE is straight line.
x=DFE=51
In a triangle ΔABC, we have
y=x+83 ....Exterior angle property of triangle ABC
y=51+83
y=134
x+y=51+134=185

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