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Question

In the figure, O is the centre of the circle with AOB=85 and AOC=115, then BAC is :

84631_ab67062fead84fe3a130239cef521acf.png

A
115
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B
85
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C
80
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D
100
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Solution

The correct option is C 80
BOC=36011585=160o
Angle subtended at the center is wice the angle subtended anywhere on the arc, so
BAC=12BOC=80o
So option C is the right answer.

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