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Area of a Circle

In the figure...

Question

In the figure, $O$ is the point of intersection of two chords $A B$ and $C D$ such that $O B = O D$ , then triangles $O A C$ and $O D B$ are:

A

Equilateral but not similar

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B

Isosceles but not similar

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C

Equilateral and similar

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D

Isosceles and similar

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Solution

The correct option is D Isosceles and similar
Length of $O B = O D a n d O C = O A$
so it is isosceles
$O A = O B = O C = O D =$ radius of circle
So it is similar.

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