In the figure, OP and OQ are opposite rays then value of ∠DOC is

40^o

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100^o

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20^o

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50^o

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Solution

The correct option is D
50^o

Sum of the angles on a straight line = 180^o

Hence, x + (x + 10)^o + (x + 20)^o = !80^o.

Solving the equation for x

We get, x = 50^o

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Similar questions

In the figure, OP, OQ, OR and OS are four rays.
Prove that: $∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S = 360^{\circ}$

In the figure below, OP, OQ, OR and OS are four rays. Then, find $\frac{(∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S)}{3}$ .

O P, O Q, O R

O S

∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S = 360^{o}

- - \to O P, - - \to O Q, - - \to O R

- - \to O S

∠ P O Q + ∠ Q O R + ∠ S O R + ∠ P O S = 360^{o}

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