Question

In the figure, PC is the tangent to the circle. A and B are 2 points on the circle. If $\angle$BPC = ${60}^0$ and $\angle$APB = ${55}^0$, then find $\angle$ABP .

• A. 55°
• B. 60°
• C. 65°
• D. 70°

Answer 1

The correct option is C

65°

Using Tangent-Chord theorem, $\angle$APD = $\angle$ABP

Therefore $\angle$ABP = ${180}^0$ – ${55}^0$ – ${60}^0$

= ${65}^0$