In the figure, PC is the tangent to the circle. A and B are 2 points on the circle. If $∠$ BPC $= 60^{0}$ and $∠$ APB $= 55^{0}$ , then find $∠$ ABP .

55°

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60°

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65°

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70°

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Solution

The correct option is C
65°

Using Tangent-Chord theorem, $∠$ APD $= ∠$ ABP

Therefore, $∠$ ABP $= 180^{\circ} - 55^{\circ} - 60^{\circ}$

$= 65^{\circ}$

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