Question

In the figure, POQ is a line, $\angle POR=4x$ and $\angle QOR=2x$. Find the value of $x$.

• A. ${30}^o$
• B. ${60}^o$
• C. ${90}^o$
• D. ${120}^o$

Answer 1

The correct option is A ${30}^o$

$\angle POR+\angle QOR={180}^o$ (Linear pair axiom)

But $\angle POR=4x$ and $\angle QOR=2x$

Therefore, $4x+2x={180}^o$

$6x={180}^o$

$x={30}^o$