Question

In the figure $PQ$ is tangent to the circle at $pt$.
Find the radius, if $PQ=8cm$ and $OR=10cm$.

Answer 1

Given: $PQ=8$cm $:QO=10$cm

To find: Radius $=OP$

In $\Delta OPQ$, using Pythagoras theorem

$(OP{)}^2+(PQ{)}^2=(OQ{)}^2$

$(OP{)}^2+(8{)}^2=(10{)}^2$

$(OP{)}^2=(100-64)c{m}^2$

$(OP{)}^2=36c{m}^2$

$OP=6cm=$Radius.