In the figure, PQ || RS, ∠AEF=950, ∠BHS=1100 and ∠ABC=x0. Then the value of x is
In the figure,
PQ || RS, ∠AEF=950
∠BHS=1100,∠ABC=x
∵ PQ || RS,
∴∠AEF=∠1=950
(Corresponding angles)
But ∠1+∠2=1800 (Linear pair)
⇒∠2=1800−∠1=1800−950=850
In Δ AGH,
Ext. ∠BHS=∠+x
⇒1100=850+x
⇒x=1100−850=250