Question

IN the figure, PQRS is a parallelogram with an area of 72 $\text{c}{\text{m}}^{\text{2}}$.

If SR=16 cm, find the altitude of triangle SRT.

Answer 1

$\text{area of paralldigram = 72 c}{\text{m}}^{{\text{2}}^{\text{'}}}$

$\text{SR = 16cm}$

$\text{Area of paradigram =}\frac{\text{1}}{2}\times \text{altitude}\times \text{SR}$

$\text{72 =}\frac{\text{1}}{2}\times \text{altitude}\times 16$

$\text{altitude =}\frac{72\times 2}{16}$

$\text{altitude = 9cm}$

$\text{so,}$

$\text{altitude of triangle SRT = 9cm}$