In the figure , PQRS is a rhombus in which the diagonal PR is produced
∠SRT=152∘, find x, y and z.
In rhombus PQRS, Diagonal PR and SQ bisect each other at right angles and PR is produced to T such that ∠SRT=152∘
But ∠SRT+∠SRP=180∘ (Linear pair)
⇒152∘+∠SRP=180∘⇒∠SRP=180∘−152∘=28∘But∠SPR=∠SRP (∵PR bisects ∠P and ∠R)⇒z=28∘ y=90∘ (∵Diagonals bisect each other at rght angles)∠RPQ=z=28∘∴In ΔPOQ,z+x=90∘⇒28∘+x=90∘⇒x=90∘−28∘=62∘∴x=62∘,y=90∘,z=28∘