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Byju's Answer

Standard XII

Physics

The 'e' Equation

In the figure...

Question

In the figure, pulley $P$ moves to the right with a constant speed $u$ . The downward speed of $A$ is $v_{A}$ , and the speed of $B$ to the right is $v_{B}$ . Then :

v_{B} = v_{A}

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v_{B} = u + v_{A}

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v_{B} + u = v_{A}

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The two blocks have accelerations of the same magnitude

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Solution

The correct options are
B $v_{B} = u + v_{A}$
D The two blocks have accelerations of the same magnitude
From figure,
$v_{B P} = v_{B} - v_{P} a n d v_{A} = v_{B} - u ∴ v_{B} = u + v_{A}$
The two blocks have accelerations of the same magnitude because they are connected by the same string.

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In the figure, pulley P moves to the right with a constant speed u. The downward speed of A is vA, and the speed of B to the right is vB. Then :

The correct options are B vB=u+vA D The two blocks have accelerations of the same magnitudeFrom figure,vBP=vB−vPand vA=vB−u∴vB=u+vAThe two blocks have accelerations of the same magnitude because they are connected by the same string.

In the figure, pulley $P$ moves to the right with a constant speed $u$ . The downward speed of $A$ is $v_{A}$ , and the speed of $B$ to the right is $v_{B}$ . Then :

The correct options are
B $v_{B} = u + v_{A}$
D The two blocks have accelerations of the same magnitude
From figure,
$v_{B P} = v_{B} - v_{P} a n d v_{A} = v_{B} - u ∴ v_{B} = u + v_{A}$
The two blocks have accelerations of the same magnitude because they are connected by the same string.