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Question
In the figure, quadrilateral ABCD is circumscribed, find the value of x.
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Solution
we know length of tangent from a point to a circle are equal
therefore AS=AP,,BP=BQ,CQ=CR,DR=DS
x=BC=BQ+QC=BP+RC=BP+CD−DR=BP+CD−DS
⇒x=5+7−3=9
therefore AS=AP,,BP=BQ,CQ=CR,DR=DS
x=BC=BQ+QC=BP+RC=BP+CD−DR=BP+CD−DS
⇒x=5+7−3=9
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