Question

In the figure, Ray $PT$ is the bisector of $\angle QPR$. Find the value of $x$ and the perimeter of $△PQR$.
Answer: $x=6cm$, $P\left(△PQR\right)=21.6cm$
If true then enter 1 else if False enter 0

Answer 1

PT bisects $\angle PQR$,
Thus, $\frac{PQ}{QT}=\frac{PR}{RT}$
$\frac{5.6}{4}=\frac{x}{5}$
$x=\frac{5.6\times 5}{4}$
$x=7$ cm
Perimeter = PQ + QR + PR
Perimeter = 5.6 + 5 + 4 + 7
$Perimeter=21.6$ cm