In the figure, $s e g P R ⊥ s e g B C, s e g A S ⊥ s e g B C a n d s e g Q T ⊥ s e g B C$ , then find the ratio
$\frac{A (△ P R C)}{A (△ B Q T)}$

\frac{R C \times P R}{B T \times Q T}

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\frac{R C \times P R}{B T \times S T}

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\frac{R B \times P R}{B T \times Q T}

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None of these

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Solution

The correct option is C $\frac{R C \times P R}{B T \times Q T}$
Area of triangle = $\frac{1}{2}$ base $\times$ height

$\frac{A (△ P R C)}{A (△ B Q T)} = \frac{\frac{1}{2} \times P R \times R C}{\frac{1}{2} \times Q T \times B T}$

$\frac{A (△ P R C)}{A (△ B Q T)} = \frac{P R \times R C}{Q T \times B T}$

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Similar questions

In adjoining figure, $P S ⊥ R Q$ and $Q T ⊥ P R$ . If $R Q = 6, P S = 6$ and $P R = 12$ , then Find $Q T$ .

P S ⊥ s e g R Q s e g Q T ⊥ s e g P R

R Q = 6, P S = 6

P R = 12

Q T

In the given figure, $R S = Q T$ and $Q S = R T .$ Then which of the following options is correct?

In the given figure, RS = QT and QS = RT. Then which of the following options is correct?

⊥

∠

40^{o}

∠

= 30^{o}

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