Question

In the figure shown a block A moving with velocity 10 m/s on a horizontal surface collides with another block B at rest initially The coefficient of restitution is $\frac{1}{2}$ Neglect friction every where The distance between the blocks 5 s after the collision takes place is 5 x (in m) Then x is

Answer 1

$e=\frac{velocityofseparation}{velocityofapproach}$

$\frac{1}{2}=\frac{velocityofseparation}{velocityofapproach}$

$\frac{1}{2}=\frac{v_1+v_2}{10}$

$({(v}_1+v_2)=5m/s$

${(v}_1+v_2)$is the ralative velocity between A and B.

distance cover in $5sec=5\times 5$

$=25m$