Question

In the figure shown, a block A moving with velocity 10 m/s on a horizontal surface collides with another block B at rest initially. The coefficient of restitution is $\frac{1}{2}$. Neglect fricition every where. The distance between the blocks 5s after the collision takes place is $5\times \left(inm\right)$, then c is :

Answer 1

Since velocity of approach $=10m/s$
So velocity of separation $=5m/s$
Therfore separation after 5 sec. from collision $=25m$