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Question

In the figure shown, a liquid is flowing through a tube at the rate of 0.1 m3/sec. The tube is randed into two semicircular tubes of cross sectional area A3 and 2A3. The velocity of liquid at Q is VQ and Velocity at P is VP (The cross-sectional area of the main is A)


A

If VP = 10 m/s, then VQ = 5 m/s

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B

If VP = 20 m/s, then VQ = 5 m/s

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C

If VP = 20 m/s, then VQ = 10 m/s

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D

If VP = 30 m/s, then VQ = 20 m/s

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Solution

The correct option is B

If VP = 20 m/s, then VQ = 5 m/s


Equation of continuity

Rate (r)=A3Vp+(AA3) VQ

VP+2VQ=3rA=3×0.1102=30m/s


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